$H C l+H_{2} O \rightleftharpoons H_{3} O^{+}+C l^{-}$
$\mathrm{Cl}^{-}$ is conjugate base of $\mathrm{HCl} \& \mathrm{H}_{3} \mathrm{O}^{+}$ is conjugate acid of $\mathrm{H}_{2} \mathrm{O}$
Stronger acids has weaker conjugate base aciding order:
$R C O O H>H C \equiv C H>N H_{3}>R H$
So basicity order : $R C O O^{-} < H C \equiv C^{-} < N H_{2}^{-} < R^{-}$
$(I)$ $ CH_3 - NO_2$
$(II)$ $NO_2 - CH_2 - NO_2$
$(III)$ $ CH_3 - CH_2 - NO_2 $
$(IV)$ $\begin{array}{*{20}{c}}
{N{O_2} - CH - N{O_2}} \\
{|\,\,\,\,\,\,} \\
{\,N{O_2}}
\end{array}$


