AB is a diameter of the circle APBR as shown in the figure. APQ and RBQ are straight lines. Find: ∠ BPR
Exercise 17 (A) | Q 29.3 | Page 260
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ABP = 90°- ∠BAP = 90° - 35° = 55°
∴ ∠ABR = ∠PBR = ∠ABP = 115° - 55° = 60°
∴ ∠APR = ABR = 60°
(Angles subtended by the same chord on the circle are equal)
∴ ∠BPR = 90° - ∠APR = 90° - 60° = 30°
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