In the given figure, AB is a diameter of the circle. Chord ED is parallel to AB and ∠EAB = 63°. Calculate : ∠ BCD.
Exercise 17 (A) | Q 37.2 | Page 260
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AB || ED
Therefore ∠DEB = EBA = 27° (Alternate angles)
Therefore BCDE is a cyclic quadrilateral
Therefore ∠DEB + ∠BCD = 180°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
Therefore ∠BCD =180° - 27° =153°
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