Question
$\text{ABCD}$ is a parallelogram and $E$ is a point on $BC$ . If the diagonal $BD$ intersects $AE$ at $F$ , prove that
$A F \times F B=E F \times F D$
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Answer

Given: $\text{ABCD}$ is a parallelogram and $E$ is a point on $BC$ . The diagonal $BD$ intersects $AE$ at $F .$
To prove: $A F \times F B=E F \times F D$
Proof: Since ABCD is a parallelogram, then its opposite sides must be parallel.
$\therefore$ In $\triangle A D F$ and $\triangle E B F$
$\angle FDA =\angle EBF$ and $\angle F A D=\angle F E B$ [Alternate interior angles]
$\angle A F D=\angle B F E$ [vertically opposite angles]
Therefore,by $\text{AAA}$ criteria of similar triangles, we have,
$\triangle ADF=\triangle EBF$
Since the corresponding sides of similar triangles are proportional. Therefore,we have,
$\frac{A F}{F D}=\frac{E F}{F B}$
$\Rightarrow A F \times F B=E F \times F D$

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