Question
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Answer
Given, AD = BC and $\angle\text{ DAB }= \angle\text{CBA }$
- In $\triangle\text{ABD},\triangle\text{BAC},$
AB = BA (Common)
$\angle\text{ DAB }= \angle\text{CBA }$ (Given)
AD = BC (Given)
Therefore, $\triangle\text{ABCD}\cong\triangle\text{BAC}$ by SAS congruence condition.
- Since, $\triangle\text{ABCD}\cong\triangle\text{BAC}$
Therefore BD = AC by CPCT
- Since, $\triangle\text{ABCD}\cong\triangle\text{BAC}$
Therefore $\angle\text{ DAB }= \angle\text{CBA }$ by CPCT.
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