Question
$\text{ABCD}$ is a rectangle with $\angle ADB = 55^\circ ,$ calculate $\angle ABD.$
✓
Answer
In $\triangle ABD,$
$\angle ADB = 55^\circ $
$\angle DAB = 90^\circ ...($in rectangle angle between two sides is $90^\circ )$
$\angle ADB + \angle DAB + \angle ABD = 180^\circ $
$55^\circ + 90^\circ + \angle ABD = 180^\circ $
$\angle ABD = 180^\circ - 145^\circ $
$\angle ABD = 35^\circ .$
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