Question
ABCD is a rectangle with $\angle\text{ABD}=40^\circ$. Determine $\angle\text{DBC}$.
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Answer
$\angle\text{ABC}=90^\circ$$\Rightarrow\angle\text{ABD}+\angle\text{DBC}=90^\circ$
$\Rightarrow40^\circ+\angle\text{DBC}=90^\circ$
$\Rightarrow\angle\text{DBC}=50^\circ$
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