$\text{ABCD}$ is a parallelogram and $E$ is the mid $-$ point of $BC. DE$ and $AB$ when produced meet at $F$. Then $,AF =$
- A$\frac{3}{2}\text{AB}$
- ✓$2\text{AB}$
- C$3\text{AB}$
- D$\frac{5}{4}\text{AB}$
Answer: B.
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