MCQ
ABCD is a Rhombus such that $\angle A C B=40^{\circ}$, then $\angle A D B$ is
- A$100^{\circ}$
- B$40^{\circ}$
- C$60^{\circ}$
- D$50^{\circ}$
✓
Answer
(d) $50^{\circ}$
Explanation : In Rhombus, digonals bisect each other right angle. By using angle sum property in any of the four triangles formed by intersection of diagonals, we get $\angle C B D=50$ and $\angle C B D=\angle A D C$ ( alternate angles).
So, $\angle ADC =50$
Explanation : In Rhombus, digonals bisect each other right angle. By using angle sum property in any of the four triangles formed by intersection of diagonals, we get $\angle C B D=50$ and $\angle C B D=\angle A D C$ ( alternate angles).
So, $\angle ADC =50$
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