MCQ
According to Bohr's theory, the angular momentum of an electron in $5^{th}$ orbit is
- A$10\, h/\pi$
- ✓$2.5 \, h/\pi$
- C$25 \, h/\pi$
- D$1.0 \, h/\pi$
✓
Answer
Correct option: B.
$2.5 \, h/\pi$
b
Formula of angular momentum of an electron,
Formula of angular momentum of an electron,
$\mathrm{mvr}=\frac{n h}{2 \pi}$
here $n=5$
$\therefore \mathrm{mvr}=\frac{5 h}{2 \pi}=2.5 \frac{h}{\pi}$
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