MCQ
The silicate anion in the mineral kinoite is a chain of three $SiO_4$ tetrahedra that share corners with adjacent tetrahedra. The mineral also contains $Ca^{2+}$ ions, $Cu^{2+}$ ions, and water molecules in a $1 : 1 : 1$ ratio mineral is represented as:
  • A
    $CaCuSi_3O_{10} · H_2O$
  • B
    $CaCuSi_3O_{10} · 2H_2O$
  • $Ca_2Cu_2Si_3O_{10} · 2H_2O$
  • D
    none of these

Answer

Correct option: C.
$Ca_2Cu_2Si_3O_{10} · 2H_2O$
c
As it shares corner with next so it forms linear structure with $\left(\mathrm{Si} \mathrm{O}_{3}\right)_{\mathrm{n}}^{-2 \mathrm{n}} .$ Therefore, three unit will have total negative charge of eight and positive charge will be same, so formula is - $\mathrm{Ca}_{2} \mathrm{Cu}_{2} \mathrm{Si}_{3} \mathrm{O}_{10} \cdot 2 \mathrm{H}_{2} \mathrm{O}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions