Question
According to de-Broglie, a moving material particle sometimes acts as a wave and sometimes as a particle or a wave associated with moving material particle which controls the particle in every respect. The wave associated with moving particle is called matter wave or de-Broglie wave where wavelength called de-Broglie wavelength, rs given by $\lambda=\frac{\text{h}}{\text{mv}}$.
- If a proton and an electron have the same de Broglie wavelength, then:
- Kinetic energy of electron < kinetic energy of proton.
- Kinetic energy of electron = kinetic energy of proton.
- Momentum of electron = momentum of proton.
- momentum of electron < momentum of proton.
- Which of these particles having the same kinetic energy has the largest de Broglie wavelength?
- Electron
- Alpha particle
- Proton
- Neutron
- Two particles $A_1$ and $A_2$ of masses $m_1, m_2 (m_1 > m_2)$ have the same de Broglie wavelength. Then:
- Their momenta are the same.
- Their energies are the same.
- Momentum of $A_1$ is less than the momentum of $A_1$.
- Energy of $A_1$ is more than the energy of $A_2.$
- When the velocity of an electron increases, its de Broglie wavelength:
- Increases.
- Decreases.
- Remains same.
- May increase or decrease.
- Proton and $\alpha$ - particle have the same de-Broglie wavelength. What is same for both of them?
- Time period
- Energy
- Frequency
- Momentum

