According to Joule's law, if the potential difference across a conductor having a material of specific resistance remains constant, then the heat produced in the conductor is directly proportional to
Medium
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(d) $P = \frac{{{V^2}}}{R}$ but $R = \frac{{\rho l}}{A}$ $ \Rightarrow $ $P = \frac{{{V^2}}}{{\rho l/A}} = \frac{{A{V^2}}}{{\rho l}}$. Since $\frac{{A{V^2}}}{l}$is constant as per given conditions So $P \propto \frac{1}{\rho }$.
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$AB$ is a wire of uniform resistance. The galvanometer $G$ shows no current when the length $AC = 20\,cm$ and $CB = 80\, cm$. The resistance $R$ is equal to .............. $\Omega $
In a Wheatstone bridge, $P = 90\,\Omega $, $Q = 110\,\Omega $ , $R = 40\,\Omega $ and $S = 60\,\Omega $ and a cell of $4\,V\,emf$. Then the potential difference between the diagonal along which a galvanometer is connected is ............. $V$
There are three resistance coils of equal resistance. The maximum number of resistances you can obtain by connecting them in any manner you choose, being free to use any number of the coils in any way is
Eight copper wire of length $l$ and diameter $d$ are joined in parallel to form a single composite conductor of resistance $R$. If a single copper wire of length $2\,l$ have the same resistance $(R)$ then its diameter will be $.....d$.