Question
According to the figure, if the coefficient of static friction between block of mass 2 kg and the table is $\mu_s=0.2$ then what should be the maximum value of $m$ so that the block does not move while the pulley is light and frictionless.
✓
Answer
Given
$\begin{array}{l}
M=2 kg \\
\mu_s=0.2
\end{array}$
Maximum value of $m=$ ?
$\begin{array}{rlrl}
\Rightarrow & Mg \times \mu_s & =m g \\
\Rightarrow & M \times \mu_s & =m \\
\therefore & m =2 \times 0.2 \\
&=0.4 kg\quad \text { Ans. }
\end{array}$
$\begin{array}{l}
M=2 kg \\
\mu_s=0.2
\end{array}$
Maximum value of $m=$ ?
$\begin{array}{rlrl}
\Rightarrow & Mg \times \mu_s & =m g \\
\Rightarrow & M \times \mu_s & =m \\
\therefore & m =2 \times 0.2 \\
&=0.4 kg\quad \text { Ans. }
\end{array}$
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