MCQ
According to the reaction $PbC{l_2} = P{b^2} + 2C{l^ - },$the solubility coefficient of $PbC{l_2}$ is
- ✓$[P{b^{2 + }}]\,{[C{l^ - }]^2}$
- B$[P{b^{2 + }}]\,[C{l^ - }]$
- C${[P{b^{2 + }}]^2}\,[C{l^ - }]$
- DNone of these
✓
Answer
Correct option: A.
$[P{b^{2 + }}]\,{[C{l^ - }]^2}$
(a) Solubility coefficient $ = [P{b^{2 + }}]\,\,{[C{l^ - }]^2}$
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