- ASodium bisulphite
- ✓Ammonia
- CPhosphorus pentachloride
- DPhenyl hydrazine
$\begin{array}{*{20}{c}}
{2C{H_3} - C - C{H_3}} \\
{\,\,||} \\
{\,\,\,O}
\end{array}$ $ + \,N{H_3}\, \to $ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}
\end{array}} \\
{C{H_3} - C - C{H_2} - C - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
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$A$. Compound ' $B$ ' is aromatic
$B$. The completion of above reaction is very slow
$C$. '$A$' shows tautomerism
$D$. The bond lengths $C - C$ in compound $B$ are found to be same
Choose the correct answer from the options given below :
$(II)$ (figure)
$(III)\, CH_3-N=CH_2$
$(IV)\, C_2H_5-CH=N-OH$
$x\ MnO + y\ PbO_2 + z\ HNO_3 \to a\ HMnO_4 + b\ Pb(NO_3 )_2 + c\ H_2O$