MCQ
Acetaldehyde on treatment with dil. $NaOH $ followed by heating gives
- A$C{H_3}C{H_2}C{H_2}C{H_2}OH$
- B$C{H_3}C{H_2}C{H_2}CHO$
- ✓$C{H_3} - CH = CHCHO$
- D$C{H_3} - CH = CHC{H_2}OH$
✓
Answer
Correct option: C.
$C{H_3} - CH = CHCHO$
c
(c) $C{H_3}CHO\xrightarrow{{dil\,\,NaOH}}\mathop {C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,\,} }\limits_{OH} - C{H_2} - CHO}\limits_{{\text{Aldol}}} $
(c) $C{H_3}CHO\xrightarrow{{dil\,\,NaOH}}\mathop {C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,\,} }\limits_{OH} - C{H_2} - CHO}\limits_{{\text{Aldol}}} $
$\xrightarrow{{Heat}}\mathop {C{H_3} - CH = CH - CHO + {H_2}O}\limits_{} $
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