MCQ
Acetaldehyde reacts with ${C_2}{H_5}MgCl$ the final product is
- AAn aldehyde
- BA ketone
- CA primary alcohol
- ✓A secondary alcohol
✓
Answer
Correct option: D.
A secondary alcohol
d
It's Obvious.
It's Obvious.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Sodium phenoxide when heated with $CO_2$ under pressure at $125\,^o C$ yields a product which on acetylation produces $C.$ The major product $C$ would be
→Argon was discovered by
The standard electrode potential $\left( M ^{3+} / M ^{2+}\right)$ for $V$, $Cr , Mn$ and $Co$ are $-0.26\,V ,-0.41\,V ,+1.57\,V$ and $+1.97\,V$, respectively. The metal ions which can liberate $H _2$ from a dilute acid are
→Metals react differently with water. The more vigorous is the reaction, the more is the bubble formation. The following diagram illustrates the reaction of sodium, magnesium and copper with water.
What can be concluded from this diagram?
What can be concluded from this diagram?
The correct relationship between molality $(m)$ and molarity $(M)$ of a solution is ($d =$ density in $g/ml$ )
→Nucleophilic addition reaction will be most favoured in
The major product $(C)$ is
→............ grams of $NaOH$ will be required to neutralize $12.2\,grams$ of benzoic acid
→Nitration of aniline in strong acidic medium also gives m-nitroaniline because
How many $gm$ of ${H_2}S{O_4}$ is present in $0.25\,gm$ mole of ${H_2}S{O_4}$
→