MCQ
Acetaldehyde when treated with dilute $NaOH$ gives
  • A
    $C{H_3}C{H_2}OH$
  • B
    $C{H_3}COOH$
  • $C{H_3} - \mathop {\mathop C\limits^| H}\limits^{OH}  - C{H_2} - CHO$
  • D
    $C{H_3} - C{H_3}$

Answer

Correct option: C.
$C{H_3} - \mathop {\mathop C\limits^| H}\limits^{OH}  - C{H_2} - CHO$
c
(c) $2C{H_3}CHO\mathop {\xrightarrow{{{\text{dil}}{\text{.}}}}}\limits_{NaOH} C{H_3} - \mathop {\mathop C\limits^| H}\limits^{OH}  - C{H_2}CHO$

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