Acetic acid is 5% ionised in its decimolar solution. Calculate th… - Vidyadip

Question

Acetic acid is 5% ionised in its decimolar solution. Calculate the dissociation constant of acid.

✓

Answer

Given : $C =0.1 M ;$ Dissociation $=5 \%, K _{ a }=2$ Percent dissociation
$
\begin{aligned}
\alpha & =\frac{\text { Percent dissociation }}{100} \\
& =\frac{5}{100}=0.05 \\
K_{ a } & =\frac{C \alpha^2}{1-\alpha}=\frac{0.1 \times(0.05)^2}{1-0.05} \\
& =\frac{0.1 \times(0.05)^2}{0.95} \text { } \\
& =2.63 \times 10^{-4}
\end{aligned}
$
Dissociation constant of acid $= K _{ a }=2.63 \times 10^{-4}$Given : $C =0.1 M ;$ Dissociation $=5 \%, K _{ a }=2$ Percent dissociation
$
\begin{aligned}
\alpha & =\frac{\text { Percent dissociation }}{100} \\
& =\frac{5}{100}=0.05 \\
K_{ a } & =\frac{C \alpha^2}{1-\alpha}=\frac{0.1 \times(0.05)^2}{1-0.05} \\
& =\frac{0.1 \times(0.05)^2}{0.95} \text { } \\
& =2.63 \times 10^{-4}
\end{aligned}
$
Dissociation constant of acid $= K _{ a }=2.63 \times 10^{-4}$

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