MCQ
Action of hydrogen chloride on $\begin{array}{*{20}{c}}
{C{H_3} - C = C{H_2}} \\
|\,\,\, \\
\,\,\,{C{H_3}}
\end{array}$ and on $CH \equiv CH$ will predominantly give the compounds, respectively :-
{C{H_3} - C = C{H_2}} \\
|\,\,\, \\
\,\,\,{C{H_3}}
\end{array}$ and on $CH \equiv CH$ will predominantly give the compounds, respectively :-
- A$\begin{array}{*{20}{c}}
{C{H_3} - CH = C{H_2}Cl} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,}
\end{array}$ and $CH_2Cl-CH_2Cl$ - ✓$\begin{array}{*{20}{c}}
{C{H_3} - CCl = C{H_3}} \\
{|\,\,\,\,\,\,\,} \\
{C{H_3}}\,\,
\end{array}$ and $CH_3-CHCl_2$ - C$\begin{array}{*{20}{c}}
{C{H_3} - CH = C{H_2}Cl} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,}
\end{array}$ and $CH_3-CHCl_2$ - D$\begin{array}{*{20}{c}}
{C{H_3} - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,} \\
{C{H_3}}\,\,\,\,
\end{array}$ and $CH_2Cl-CH_2Cl$
