MCQ
Hydrogen bonding does not play any role in boiling of
- A$N{H_3}$
- B${H_2}O$
- ✓$HI$
- D${C_2}{H_5}OH$
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take place in two steps :
$(a)$ $Br^{-} + H^{+} + H_2O_2 \xrightarrow{{slow}} HOBr + H_2O$
$(b)$ $HOBr + Br^{-} + H^{+} \xrightarrow{{fast}} H_2O + Br_2$
The order of the reaction is
