Question
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Answer
Given,
AD and BC are equal perprndiculars to AB.
To prove,
CD bisects AB
In $\triangle\text{AOD}$ and $\triangle\text{BOC}$
$\angle\text{A}=\angle\text{D}$(Perprndicular)
$\angle\text{ AOD} = \angle\text{ BOC}$ (Vertically opposite angle)
AD = BC (Given)
Therefore $\triangle \text{AOD}\cong\triangle \text{BOC}$ by AAS congruence condition.
Now,
AO = OB (CPCT). CD bisects AB.
AD and BC are equal perprndiculars to AB.
To prove,
CD bisects AB
In $\triangle\text{AOD}$ and $\triangle\text{BOC}$
$\angle\text{A}=\angle\text{D}$(Perprndicular)
$\angle\text{ AOD} = \angle\text{ BOC}$ (Vertically opposite angle)
AD = BC (Given)
Therefore $\triangle \text{AOD}\cong\triangle \text{BOC}$ by AAS congruence condition.
Now,
AO = OB (CPCT). CD bisects AB.
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