Maharashtra BoardEnglish MediumSTD 9MathsNumber System2 Marks
Question
Add:$=\big(2\sqrt{2}+5\sqrt{3}-7\sqrt{5}\big)$ and $\big(3\sqrt{3}-\sqrt{2}+\sqrt{5}\big)$
✓
Answer
We have,$=\big(2\sqrt{2}+5\sqrt{3}-7\sqrt{5}\big)+\big(3\sqrt{3}-\sqrt{2}+\sqrt{5}\big)$
$=\big(2\sqrt{2}-\sqrt{2}\big)+\big(5\sqrt{3}+3\sqrt{3}\big)+\big(-7\sqrt{5}+\sqrt{5}\big)$
$=(2-1)\sqrt{2}+(5+3)\sqrt{3}+(-7+1)\sqrt{5}$
$=\sqrt{2}+8\sqrt{3}-6\sqrt{5}.$
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