Question
Add the following expression:
$2 x^2-3 y^2, 5 x^2+6 y^2,-3 x^2-4 y^2$

Answer

$\left(2 x^2-3 y^2\right)+\left(5 x^2+6 y^2\right)+\left(-3 x^2-4 y^2\right)=4 x^2-y^2$
$\ \ \ \ 2\text{x}^2-3\text{y}^2\\+5\text{x}^2+6\text{y}^2\\-3\text{x}^2-4\text{y}^2\\ \underline{ \overline{\ \ \ \ 4\text{x}^2-\ \ \text{y}^2}}$

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