Question
Add the following rational numbers:
$\frac{-5}{9}\text{ and }\frac{2}{3}$
$\frac{-5}{9}\text{ and }\frac{2}{3}$
✓
Answer
$\frac{-5}{9}\text{ and }\frac{2}{3}$
$\frac{2}{3}=\frac{2\times3}{3\times3}=\frac{6}{9}$
$\therefore\frac{-5}{9}+\frac{2}{3}=\frac{-5}{9}+\frac{6}{9}$
$=\frac{-5+6}{9}=\frac{1}{9}$
$\frac{2}{3}=\frac{2\times3}{3\times3}=\frac{6}{9}$
$\therefore\frac{-5}{9}+\frac{2}{3}=\frac{-5}{9}+\frac{6}{9}$
$=\frac{-5+6}{9}=\frac{1}{9}$
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