MCQ
Addition of conc. $HCl$ to saturated $BaC{l_2}$ solution precipitates $BaC{l_2}$; because
  • A
    It follows from Le Chatelier’s principle
  • B
    Of common-ion effect
  • Ionic product $(B{a^{ + + }}),$$(C{l^ - })$remains constant in a saturated solution
  • D
    At constant temperature, the product $(B{a^{2 + }}),$ ${(C{l^ - })^2}$ remains constant in a saturated solution

Answer

Correct option: C.
Ionic product $(B{a^{ + + }}),$$(C{l^ - })$remains constant in a saturated solution
c
When you add a compound having a common ion, It decreases the solubility of the solute. This is because Le Chatelier's principle states the reaction will shift toward the left (toward the reactants) to relieve the stress of the excess product.

This is called common-ion effect. due to this effect, some solute becomes insoluble and precipitate.

In the above case $HCl$ and $BaCl _2$ have $Cl ^{-}$ common ions and thus $BaCl _2$ precipitates.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free