MCQ
CH3−C≡C MgBr can be prepared by the reaction of _________.
- ACH3−C≡C−Br with MgBr2
- BCH3−C≡CH with MgB2
- CCH2−C≡CH with KBr and Mg metal
- DCH3−C≡CH with CH3MgBr
Explanation:
CH3−C≡C−H + CH3MgBr → CH3−C≡CMgBr + CH4.
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(Molar mass of $\mathrm{H}_3 \mathrm{PO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1}$ )

(Given : $\left.pK _{ a }\left( CH _{3} COOH \right)=4.76\right)$
$\log 2=0.30$ $\log 3=0.48$ $\log 5=0.69$ $\log 7=0.84$ $\log 11=1.04$