MCQ
${A_{(g)}} + 3{B_{(g)}}$ $\rightleftharpoons$ $4{C_{(g)}}$. Starting concentration of $A$ is equal to $B$, equilibrium concentration of $A$ and $C$ are same. ${K_c} = $
- A$0.08$
- B$0.8$
- ✓$8$
- D$80$
$a$ $b$ $0$
$(a -x)$ $(b -3x)$ $4x$
${K_C} = \frac{{{{[C]}^4}}}{{[A]{{[B]}^3}}} = \frac{{4x.4x.4x.4x}}{{(a - x)(b - 3x)}}$
$a=b,\,a-x=4x\Rightarrow a=5x=b$
${{K}_{C}}=\frac{4x.4x.4x.4x}{(5x-x)(5x-3x)}=\frac{4x.4x.4x.4x}{4x.2x.2x.2x}=8$
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For this reaction which statement is false