$\text{S}=\sqrt{\text{Ksp}}=\sqrt{1.2\times {{10}^{-10}}}$
$\text{AgBr }$ નો $ \text{Ksp}=\text{3}\text{.5}\times \text{1}{{\text{0}}^{\text{-13}}}$
$S=\sqrt{Ksp}=\sqrt{3.5\times {{10}^{-13}}}$
તો $ \,\text{AgCl}\,$ તો $ \,\text{S}>\text{AgBr}$ તો $\text{S}$