i. e. carbanion formed.

$2,4,6$ -trinitrophenol after the loss of a proton gives $2,4,6$ -trinitrophenoxide ion which is stabilised by resonance, $-l-$effect and $- M-$effect, thus is most acidic among the given compounds.

Phenol after losing a proton form phenoxide ion which is also stabilised by resonance, $- M$ and $-I$ effects but is less stabilised as compared to

$2,4,6$ -trinitrophenoxide ions. Thus, it is less acidic as compared to $2,4,6$ -trinitrophenol. $\left(C H_{3} C O O H\right)$ after losing a proton gives acetate

ion which is stabilised by only resonance. However, it is more resonance stabilised as compared to a phenoxide ion, thus more acidic as compared to phenol. $2,4,6$ -trinitrophenol, however, is more acidic than acetic acid due to the presence of three

electron withdrawing $-N O_{2}$ groups. Cyclohexanol gives an anion that is least stable among the given, thus, it is least acidic.

Hence, the correct order of acidic strength is

$2,4,6$ -trinitrophenol > acetic acid > phenol > cyclohexanol

$I I I>I I>I V>I$