i. e. carbanion formed.
\(2,4,6\) -trinitrophenol after the loss of a proton gives \(2,4,6\) -trinitrophenoxide ion which is stabilised by resonance, \(-l-\)effect and \(- M-\)effect, thus is most acidic among the given compounds.
Phenol after losing a proton form phenoxide ion which is also stabilised by resonance, \(- M\) and \(-I\) effects but is less stabilised as compared to
\(2,4,6\) -trinitrophenoxide ions. Thus, it is less acidic as compared to \(2,4,6\) -trinitrophenol. \(\left(C H_{3} C O O H\right)\) after losing a proton gives acetate
ion which is stabilised by only resonance. However, it is more resonance stabilised as compared to a phenoxide ion, thus more acidic as compared to phenol. \(2,4,6\) -trinitrophenol, however, is more acidic than acetic acid due to the presence of three
electron withdrawing \(-N O_{2}\) groups. Cyclohexanol gives an anion that is least stable among the given, thus, it is least acidic.
Hence, the correct order of acidic strength is
\(2,4,6\) -trinitrophenol > acetic acid > phenol > cyclohexanol
\(I I I>I I>I V>I\)
$\left. \begin{gathered}
(A)\,\,\xrightarrow{{PB{r_3}}}\,(C)\,\xrightarrow{{Mg\,,\,ether}}Grignard\,\,reagent \hfill \\
(A)\,\,\xrightarrow[{{H_2}S{O_4}}]{{N{a_2}C{r_2}{O_7}}}\,(B) \hfill \\
\end{gathered} \right\}$ $ \to \,(D)\xrightarrow{{{H_3}{O^ \oplus }}}$ $(3,4-$ ડાયમિથાઇલ $3-$ હેકઝાનોલ l$)$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{C{H_3} - CH = CH - C{H_2} - CH - C{H_3}}
\end{array}$ $\longrightarrow $ $C{H_3} - CH = CH - C{H_2}C{O_2}H$
${C_3}{H_7}OH\xrightarrow{{conc\,{H_2}S{O_4}}}X\xrightarrow{{B{r_2}}}Y\xrightarrow[{alkolic\,KOH}]{{high\,level}}Z$
સંયોજન $'C'$ શું હશે ?