MCQ
અહિ $A=\left[\begin{matrix}1&-1&1\\2&1&-3\\1&1&1\end{matrix} \right]$ અને $10B=\left[\begin{matrix}4&2&2 \\-5&0&\alpha \\1&-2&3\end{matrix}\right]$ જો $B$ એ $A$ નો વ્યસ્ત શ્રેણીક હોય તો $\alpha=.....$
- A2
- ✓5
- C3
- D3
$10I=10(AB)=A(10B)$
$\therefore10\left[\begin{matrix}1&0&0\\0&1&0\\0&0&1\end{matrix}\right]=\left[\begin{matrix}1&-1&1\\2&1&-3 \\1&1&1 \end{matrix}\right]\left[\begin{matrix}4&2&2\\-5&0&\alpha\\1&-2&3\end{matrix}\right]$
$\therefore\left[\begin{matrix}10&0&0\\0&10&0\\0&0&10\end{matrix}\right]=\left[\begin{matrix}10&0&5-\alpha\\0&10 &\alpha-5 \\0&0&5+\alpha\end{matrix}\right]$
$\therefore5-\alpha=0\ \ \ \ $
$\therefore \alpha=5.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.