where $a, b, c, d \in\{\pm 3, \pm 2, \pm 1,0\}$
Case $\mathrm{I} \mathrm{ad}=9 \,\& \,\mathrm{bc}=-6$
For ad possible pairs are $(3,3),(-3,-3)$
For bc possible pairs are $(3,-2),(-3,2),(-2,3),\left(2_{6}-3\right)$
So total matrix $=2 \times 4=8$
Case $II$ ad $=6 \,\&\, \mathrm{bc}=-9$
Similarly total matrix $=2 \times 4=8$
$\Rightarrow$ Total such matrices are $=16$
$\left[\begin{array}{cc}
2 a+b & a-2 b \\
5 c-d & 4 c+3 d
\end{array}\right]=\left[\begin{array}{cc}
4 & -3 \\
11 & 24
\end{array}\right]$