- A$1400$
- B$149$
- C$494$
- D$1494$
$\vec{b}=\hat{i}+2 \hat{j}-\hat{k}$
$\vec{c}=3 \hat{i}+2 \hat{j}-\hat{k}$
$\vec{v}=x \vec{a}+y \vec{b} \quad \vec{v}(3 \hat{i}+2 \hat{j}-k)=0$
$\vec{v} \cdot \hat{a}=19$
$\vec{v}=\lambda \vec{c} \times(\vec{a} \times \vec{b})$
$\vec{v}=\lambda[(\vec{c} \cdot \vec{b}) \vec{a}-(\vec{c} \cdot \vec{a}) \vec{b}]$
$=\lambda\left[(3+4+1)(2 \hat{i}-\hat{j}+2 \hat{k})-\left(\frac{6-2-2}{2}\right)(\hat{i}+2 \hat{j}+\hat{k})\right.$
$=\lambda[16 \hat{i}-8 \hat{j}+16 \hat{k}-2 \hat{i}-4 \hat{j}+2 \hat{k}]$
$\vec{v}=\lambda[14 \hat{i}-12 \hat{j}+18 \hat{k}]$
$\lambda[14 \hat{i}-12 \hat{j}+18 \hat{k}] \cdot \frac{(2 \hat{i}-\hat{j}+2 \hat{k})}{\sqrt{4+1+4}}=19$
$\lambda \frac{[28+12+36]}{3}=19$
$=\left(\frac{76}{3}\right)=19$
$4 \lambda=3 \Rightarrow \lambda=\frac{3}{4}$
$=2 v^{2}|=| 2 \times\left.\frac{3}{4}(14 \hat{i}-12 \hat{j}+18 \hat{k})\right|^{2}$
$=9(49+36+81)$
$=9(166)$
$=1494$
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