Air of density $1.2\,kg\,m^{-3}$ is blowing across the horizontal Wings of an aeroplane in such a way that its speeds above and below the wings are $150\,ms^{-1}$ and $100\,ms^{-1}$, respectively. The pressure difference between the upper and lower sides of the Wings, is ........ $Nm^{-2}$
JEE MAIN 2013, Medium
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Pressure difference
${P_2} - {P_1} = \frac{1}{2}\rho \left( {v_2^2 - v_1^2} \right)$
$ = \frac{1}{2} \times 1.2\left( {{{\left( {150} \right)}^2} - {{\left( {100} \right)}^2}} \right)$
$ = \frac{1}{2} \times 1.2\left( {22500 - 10000} \right)$
$ = 7500\,N{m^{ - 2}}$
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