MCQ
$AlCl_3$ on hydrolysis gives:
- A$Al_2O_3 .H_2O$
- ✓$Al(OH)_3$
- C$Al_2O_3$
- D$AlCl_3.6H_2O$
✓
Answer
Correct option: B.
$Al(OH)_3$
b
$\mathrm{AlCl}_{3}$ on hydrolysis gives $\mathrm{Al}(\mathrm{OH})_{3}$
$\mathrm{AlCl}_{3}$ on hydrolysis gives $\mathrm{Al}(\mathrm{OH})_{3}$
Hydrolysis is breaking with the help of water.
$\mathrm{AlCl}_{3}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Al}(\mathrm{OH})_{3}+3 \mathrm{HCl}$
Hence option B is correct.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Select the correct order
If $n$ & $l$ are principal and azimuthal quantum no. respectively then the expression for calculating the total no. of electron in any energy level is :-
→What will be the $pH$ of a ${10^{ - 8}}\,M\,HCl$ solution
→$\,$
→The $IUPAC$ name of the compound is $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,Ph} \\
{\,\,\,\,\,\,\,\,|} \\
{C{H_3} - CH - CH - N{H_2}} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,}
\end{array}$
→{\,\,\,\,\,\,\,\,\,\,Ph} \\
{\,\,\,\,\,\,\,\,|} \\
{C{H_3} - CH - CH - N{H_2}} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$2\,mol$ of zinc is dissolved in $HCl$ at $25\,^oC.$ The work done is open vessel
→Among the following statements on the nitration of aromatic compounds, the false one is
Solubility product expression of salt $MX_4$ which is sparingly soluble with a solubility $(S)$ can be given as
→Number of angular nodes for 4d orbital is _________ .
Which is optically active