MCQ
$A=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$ then $A^2=$
  • A
    $\left[\begin{array}{ll}1 & 1 \\ 0 & 0\end{array}\right]$
  • B
    $\left[\begin{array}{ll}0 & 0 \\ 1 & 1\end{array}\right]$
  • $\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$
  • D
    $\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]$

Answer

Correct option: C.
$\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$
Given
$
\begin{aligned}
& A=\left[\begin{array}{ll}
1 & 0 \\
0 & 1
\end{array}\right] \\
& A^2=A \times A=\left[\begin{array}{ll}
1 & 0 \\
0 & 1
\end{array}\right] \times\left[\begin{array}{ll}
1 & 0 \\
0 & 1
\end{array}\right] \\
& =\left[\begin{array}{ll}
1+0 & 0+0 \\
0+0 & 0+1
\end{array}\right] \\
& =\left[\begin{array}{ll}
1 & 0 \\
0 & 1
\end{array}\right] . \\
&
\end{aligned}
$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free