All capacitors used in the diagram are identical and each is of capacitance $C$. Then the effective capacitance between the points $A$ and $B$ is
Medium
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First three capacitors are in parallel and last three are also in parallel. Both the groups are in series.
$\therefore C_{e q}=3 \mathrm{C} / 2=1.5 \mathrm{C}$
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