In one design of capacitor thin sheets ot metal of area $80\  mm \times 80\  mm$ sandwich between them a piece of paper whose thickness is $40\ μm$. The relative permittivity of the paper is $4.0$ and its dielectric strength is $20\ MVm^{-1}$. Calculate the maximum charge that can be put on the capacitor

[permittivity of free space $ = 9 \times 10^{-12}\  Fm^{-1}$]

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$\mathrm{E}_{\max }=20 \times 10^{6}-\frac{\mathrm{V}}{\mathrm{d}}$

$\mathrm{V}=20 \times 10^{6} \times 40 \times 10^{-6}=800$

$Q_{\max }=C V=\frac{K \epsilon_{0} A}{d} V$

$ = \frac{{4 \times 5 \times {{10}^{ - 12}} \times 6400 \times {{10}^{ - 6}}}}{{40 \times {{10}^{ - 6}}}} \times 800$

$=4608 \times 10^{-9} \mathrm{\,C}$

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