All the six capacitors shown in the circuit are identical. Each can withstand maximum $200\, volt$ between its terminals. The maximum voltage that can be applied safely between $A$ and $B$ is.....$V$
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for max $^{m} V_{A B},$ these two voltages should be added
$\Rightarrow \mathrm{V}_{\mathrm{AB} \max } =(200+200) \mathrm{V} $
$=400 \mathrm{\,V}$
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