A wire suspended vertically from one end is stretched by attaching a weight $200 \,N$ to the lower end. The weight stretches the wire by $1 \,mm$. The elastic potential energy gained by the wire is ....... $J$
A$0.1$
B$0.2$
C$0.4$
D$10$
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A$0.1$
a (a)
Elastic potential energy $=\frac{1}{2} \times$ force $\times$ elongation
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