Although $+3$ is the characteristic oxidation state for lanthanoids but cerium also shows $+4$ oxidation state because $.......$
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Cerium shows $+4$ oxidation state also because it has a tendency to attain noble gas configuration and attain $f^\circ$ configuration. $\ce{Ce – 4f^{1 } 5d\ ’ 6s^2 (Ce^{4+ }– 4f^\circ )}$
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