MCQ
Amide which gives propanamine by Hoffmann bromamide is:
  • Pentanamide
  • B
    Hexanamide
  • C
    Butanamine
  • D
    Propanamine

Answer

Correct option: A.
Pentanamide
In the Hoffmann bromamide reaction, the amine formed has one carbon less than that present in the amide. $\ce{RCONH_2 + Br_2 + 4NaOH} \rightarrow \ce{RNH_2 + Na_2CO_3 + 2NaBr + 2H_2O}$

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