XeF_2 reacts with PF_5 to give - Vidyadip

MCQ

$XeF_2$ reacts with $PF_5$ to give

A
$XeF_6$
✓
$[XeF]^+ [PF_6]^-$
C
$XeF_4$
D
$[PF_4]^+ [XeF_3]^-$

✓

Answer

Correct option: B.

$[XeF]^+ [PF_6]^-$

b
$PF _5$ is a fluoride ion acceptor so it yields cationic species with xenon fluorides.

$\left[ XeF _2\right]+\left[ PF _5\right] \rightarrow[ XeF ]^{+}\left[ PF _6\right]^{-}$

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