MCQ
Ammonia with excess of $Cl_2$, forms
- ANitrogen
- BNitrosyl chloride
- CAmmonium chloride
- ✓Nitrogen trichloride
$8 NH _3( g )+3 Cl _2( g ) \rightarrow 6 NH _4 Cl ( s )+ N _2( g )$
But in excess of chlorine, ammonia forms nitrogen trichloride.
$3 Cl _2+ NH _3 \rightarrow NCl _3+3 HCl$
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$F{e^{ + 3}}\left( {aq} \right) + {e^ - } \to F{e^{2 + }}\left( {aq} \right);{E^o} = + 0.77\,V$
$A{l^{ + 3}}\left( {aq} \right) + 3{e^ - } \to Al\left( s \right);{E^o} = - 1.66\,V$
$B{r_2}\left( {aq} \right) + 2{e^ - } \to 2B{r^ - };{E^o} = + 1.09\,V$
Considering the electrode potentials, which of the following represents the correct order of reducing power?
$ 3 \mathrm{ROH}+\mathrm{PCl}_3 \rightarrow 3 \mathrm{RCl}+\mathrm{A} $
$ \mathrm{ROH}+\mathrm{PCl}_5 \rightarrow \mathrm{RCl}+\mathrm{HCl}+\mathrm{B}$