MCQ
Among all the parallelograms whose diagonals are $10$ and $4$,the one having maximum area has its perimeter lying in the interval
- A$(19,20]$
- B$(20,21]$
- ✓$(21,22]$
- D$(22,23]$
Area of parallelogram whose diagonals are 10 and 4 and if angle between adjacent side is $\theta$ is
$A=\frac{10 \times 4}{\sin \theta}$
The area will be maximum if $\theta=\frac{\pi}{2}$, so the parallelogram must be rhombus
Perimeter of rhombus
$=4 \sqrt{2} \overline{9}=\sqrt{46} \overline{4} \text { and } \sqrt{46} \overline{4} \in(21,22]$
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