MCQ
Among the compound's the order of decreasing reactivity towards electrophilic substitution is


- A$II > I > III > IV$
- B$III > I > II > IV$
- ✓$III > I > IV > II$
- D$II > I > IV > III$

While $H _2 O$ is having lone pair so it acts as lewis base not electron defecient. (Lewis acid)
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