MCQ
Among the fluorides below, the one which does not exist is
- A$Xe{F_4}$
- ✓$He{F_4}$
- C$S{F_4}$
- D$C{F_4}$
✓
Answer
Correct option: B.
$He{F_4}$
b
(b) $He{F_4}$ does not exist.
(b) $He{F_4}$ does not exist.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The major product of the reaction is
Solid sodium chloride is bad conductor of electricity because
If the $\Delta G$ of a cell reaction $AgCl + {e^ - } \to Ag + C{l^ - }$ is $ - 21.20\;KJ$; the standard e.m.f., of cell is ............ $\mathrm{V}$
→$A $ will be
→An aqueous solution of hydrazine $\left( N _2 H _4\right)$ is electrochemically oxidized by $O _2$, thereby releasing chemical energy in the form of electrical energy. One of the products generated from the electrochemical reaction is $N _2( g )$.
→Choose the correct statement($s$) about the above process
$(A)$ $OH ^{-}$ions react with $N _2 H _4$ at the anode to form $N _2( g )$ and water, releasing 4 electrons to the anode.
$(B)$ At the cathode, $N _2 H _4$ breaks to $N _2( g )$ and nascent hydrogen released at the electrode reacts with oxygen to form water.
$(C)$ At the cathode, molecular oxygen gets converted to $OH ^{-}$.
$(D)$ Oxides of nitrogen are major by-products of the electrochemical process.
The transition metal ions responsible for colour in ruby and emerald are, respectively
A graph was plotted between molar conductivity of various electrolytes ($NaCl, HCl$ and $NH_4OH$) and $\sqrt{C}$ (in $mol\, L^{-1}$). Correct setting
→An aromatic ether is not cleaved by $HI$ even at $525\, K$. The compound is
→From the stability constant (hypothetical values), given below, predict which is the strongest ligand :
The atomic radius of $Ag$ is closest to
→