MCQ
Amongst $Ni{\left( {CO} \right)_4},$ ${\left[ {Ni{{(CN)}_4}} \right]^{2 - }}$ and ${[NiC{l_4}]^{2 - }}$
  • A
    $Ni{\left( {CO} \right)_4}$ and ${\left[ {NiC{l_4}} \right]^{2 - }}$are diamagnetic and ${[Ni{(CN)_4}]^{2 - }}$ is paramagnetic
  • B
    ${\left[ {NiC{l_4}} \right]^{2 - }}$ and ${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$ are diamagnetic and $Ni{\left( {CO} \right)_4}$ is paramagnetic
  • $Ni{\left( {CO} \right)_4}$ and ${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$ are diamagnetic and ${\left[ {NiC{l_4}} \right]^{2 - }}$ is paramagnetic
  • D
    $Ni{\left( {CO} \right)_4}$ is diamagnetic and ${\left[ {NiC{l_4}} \right]^{2 - }}$ and ${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$ are paramagnetic

Answer

Correct option: C.
$Ni{\left( {CO} \right)_4}$ and ${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$ are diamagnetic and ${\left[ {NiC{l_4}} \right]^{2 - }}$ is paramagnetic
c
(c) The electronic configuration of $Ni$ in
${[Ni{(CN)_4}]^{2 - }},\,{[Ni(C{l_4})]^{2 - }}$ and $Ni{(CO)_4}$ are as following
$CO$  and $C{N^ - }$ are strong ligands so they induces pairing of electrons so their complexes are diamagnetic while $C{l^ - }$ is a weak ligand so it does not induce the pairing of electrons so its complex is paramagnetic.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free